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17x^2+2.4x-1.44=0
a = 17; b = 2.4; c = -1.44;
Δ = b2-4ac
Δ = 2.42-4·17·(-1.44)
Δ = 103.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{103.68}}{2*17}=\frac{-2.4-\sqrt{103.68}}{34} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{103.68}}{2*17}=\frac{-2.4+\sqrt{103.68}}{34} $
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